5(x^2-1)=4(x^2+1)

Solution for 5(x^2-1)=4(x^2+1) equation:

Simplifying
5(x2 + -1) = 4(x2 + 1)

Reorder the terms:
5(-1 + x2) = 4(x2 + 1)
(-1 * 5 + x2 * 5) = 4(x2 + 1)
(-5 + 5x2) = 4(x2 + 1)

Reorder the terms:
-5 + 5x2 = 4(1 + x2)
-5 + 5x2 = (1 * 4 + x2 * 4)
-5 + 5x2 = (4 + 4x2)

Solving
-5 + 5x2 = 4 + 4x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x2' to each side of the equation.
-5 + 5x2 + -4x2 = 4 + 4x2 + -4x2

Combine like terms: 5x2 + -4x2 = 1x2
-5 + 1x2 = 4 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-5 + 1x2 = 4 + 0
-5 + 1x2 = 4

Add '5' to each side of the equation.
-5 + 5 + 1x2 = 4 + 5

Combine like terms: -5 + 5 = 0
0 + 1x2 = 4 + 5
1x2 = 4 + 5

Combine like terms: 4 + 5 = 9
1x2 = 9

Divide each side by '1'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}